130021341120 has 504 divisors, whose sum is σ = 514949937840. Its totient is φ = 29858734080.

The previous prime is 130021341097. The next prime is 130021341221. The reversal of 130021341120 is 21143120031.

130021341120 is a `hidden beast` number, since 1 + 300 + 2 + 1 + 341 + 1 + 20 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 130021341093 and 130021341102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 11430796 + ... + 11442164.

Almost surely, 2^130021341120 is an apocalyptic number.

130021341120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130021341120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (257474968920).

130021341120 is an abundant number, since it is smaller than the sum of its proper divisors (384928596720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130021341120 is a wasteful number, since it uses less digits than its factorization.

130021341120 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 11441 (or 11409 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 130021341120 its reverse (21143120031), we get a palindrome (151164461151).

Subtracting from 130021341120 its reverse (21143120031), we obtain a square (108878221089 = 329967²).

The spelling of 130021341120 in words is "one hundred thirty billion, twenty-one million, three hundred forty-one thousand, one hundred twenty".