Base | Representation |
---|---|
bin | 11101100100000100011100… |
… | …111011001100001000000111 |
3 | 122001100222120211202221001010 |
4 | 131210010130323030020013 |
5 | 114020240104214330043 |
6 | 1140311143542133303 |
7 | 36246532055444361 |
oct | 3544043473141007 |
9 | 561328524687033 |
10 | 130022030230023 |
11 | 3847a0404410a8 |
12 | 126bb182a21233 |
13 | 577204275ca59 |
14 | 2417157d6bd31 |
15 | 1007288699133 |
hex | 76411cecc207 |
130022030230023 has 4 divisors (see below), whose sum is σ = 173362706973368. Its totient is φ = 86681353486680.
The previous prime is 130022030229977. The next prime is 130022030230051. The reversal of 130022030230023 is 320032030220031.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 130022030230023 - 210 = 130022030228999 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130022030230093) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21670338371668 + ... + 21670338371673.
It is an arithmetic number, because the mean of its divisors is an integer number (43340676743342).
Almost surely, 2130022030230023 is an apocalyptic number.
130022030230023 is a deficient number, since it is larger than the sum of its proper divisors (43340676743345).
130022030230023 is an equidigital number, since it uses as much as digits as its factorization.
130022030230023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 43340676743344.
The product of its (nonzero) digits is 1296, while the sum is 21.
Adding to 130022030230023 its reverse (320032030220031), we get a palindrome (450054060450054).
The spelling of 130022030230023 in words is "one hundred thirty trillion, twenty-two billion, thirty million, two hundred thirty thousand, twenty-three".
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