Base | Representation |
---|---|
bin | 111100100010111101… |
… | …1010101101010111111 |
3 | 110102121110201020002212 |
4 | 1321011323111222333 |
5 | 4112241140431142 |
6 | 135421551011035 |
7 | 12252033324233 |
oct | 1710573255277 |
9 | 412543636085 |
10 | 130022202047 |
11 | 50162163931 |
12 | 21248209a7b |
13 | c35167933a |
14 | 64164085c3 |
15 | 35aec9bd82 |
hex | 1e45ed5abf |
130022202047 has 2 divisors, whose sum is σ = 130022202048. Its totient is φ = 130022202046.
The previous prime is 130022202031. The next prime is 130022202137. The reversal of 130022202047 is 740202220031.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 130022202047 - 24 = 130022202031 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130022202547) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65011101023 + 65011101024.
It is an arithmetic number, because the mean of its divisors is an integer number (65011101024).
Almost surely, 2130022202047 is an apocalyptic number.
130022202047 is a deficient number, since it is larger than the sum of its proper divisors (1).
130022202047 is an equidigital number, since it uses as much as digits as its factorization.
130022202047 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1344, while the sum is 23.
Adding to 130022202047 its reverse (740202220031), we get a palindrome (870224422078).
The spelling of 130022202047 in words is "one hundred thirty billion, twenty-two million, two hundred two thousand, forty-seven".
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