| Base | Representation |
|---|---|
| bin | 11101100100000100101110… |
| … | …010100001111101101111000 |
| 3 | 122001101000100011210221021222 |
| 4 | 131210010232110033231320 |
| 5 | 114020241203413323000 |
| 6 | 1140311232524051212 |
| 7 | 36246542230522646 |
| oct | 3544045624175570 |
| 9 | 561330304727258 |
| 10 | 130022322011000 |
| 11 | 3847a180111501 |
| 12 | 126bb244693b08 |
| 13 | 577208b040813 |
| 14 | 2417184a02196 |
| 15 | 10072a40d2a85 |
| hex | 76412e50fb78 |
130022322011000 has 256 divisors, whose sum is σ = 322702615872000. Its totient is φ = 48865608960000.
The previous prime is 130022322010937. The next prime is 130022322011009. The reversal of 130022322011000 is 110223220031.
It is a super-2 number, since 2×1300223220110002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a self number, because there is not a number n which added to its sum of digits gives 130022322011000.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130022322011009) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 37502831267 + ... + 37502834733.
It is an arithmetic number, because the mean of its divisors is an integer number (1260557093250).
Almost surely, 2130022322011000 is an apocalyptic number.
130022322011000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130022322011000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (161351307936000).
130022322011000 is an abundant number, since it is smaller than the sum of its proper divisors (192680293861000).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130022322011000 is a wasteful number, since it uses less digits than its factorization.
130022322011000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6655 (or 6641 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 130022322011000 its reverse (110223220031), we get a palindrome (130132545231031).
The spelling of 130022322011000 in words is "one hundred thirty trillion, twenty-two billion, three hundred twenty-two million, eleven thousand".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •