Base | Representation |
---|---|
bin | 11101100100000101011110… |
… | …101010011010110101111111 |
3 | 122001101002102201002001112112 |
4 | 131210011132222122311333 |
5 | 114020244334040130421 |
6 | 1140311445221124235 |
7 | 36246601310106464 |
oct | 3544053652326577 |
9 | 561332381061475 |
10 | 130023133130111 |
11 | 3847a556a57281 |
12 | 126bb43025967b |
13 | 577218a0b7760 |
14 | 241722062366b |
15 | 100730040445b |
hex | 76415ea9ad7f |
130023133130111 has 8 divisors (see below), whose sum is σ = 140229927124560. Its totient is φ = 119845626924672.
The previous prime is 130023133130021. The next prime is 130023133130129. The reversal of 130023133130111 is 111031331320031.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 130023133130111 - 218 = 130023132867967 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130023133130161) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 7321938026 + ... + 7321955783.
It is an arithmetic number, because the mean of its divisors is an integer number (17528740890570).
Almost surely, 2130023133130111 is an apocalyptic number.
130023133130111 is a deficient number, since it is larger than the sum of its proper divisors (10206793994449).
130023133130111 is a wasteful number, since it uses less digits than its factorization.
130023133130111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 14643894505.
The product of its (nonzero) digits is 486, while the sum is 23.
Adding to 130023133130111 its reverse (111031331320031), we get a palindrome (241054464450142).
The spelling of 130023133130111 in words is "one hundred thirty trillion, twenty-three billion, one hundred thirty-three million, one hundred thirty thousand, one hundred eleven".
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