Search a number
-
+
130023540401200 = 24526151899102677
BaseRepresentation
bin11101100100000101110110…
…111100000010010000110000
3122001101010111002102120102221
4131210011312330002100300
5114020301202320314300
61140311553450250424
736246614353623655
oct3544056674022060
9561333432376387
10130023540401200
113847a745939056
12126bb524726a14
1357722235a3774
14241725c75bc2c
15100732605231a
hex764176f02430

130023540401200 has 120 divisors (see below), whose sum is σ = 317511774932400. Its totient is φ = 51155318860800.

The previous prime is 130023540401173. The next prime is 130023540401203. The reversal of 130023540401200 is 2104045320031.

It is a super-2 number, since 2×1300235404012002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (25).

It is not an unprimeable number, because it can be changed into a prime (130023540401203) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1266284262 + ... + 1266386938.

It is an arithmetic number, because the mean of its divisors is an integer number (2645931457770).

Almost surely, 2130023540401200 is an apocalyptic number.

130023540401200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130023540401200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158755887466200).

130023540401200 is an abundant number, since it is smaller than the sum of its proper divisors (187488234531200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130023540401200 is a wasteful number, since it uses less digits than its factorization.

130023540401200 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 154655 (or 154644 counting only the distinct ones).

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 130023540401200 its reverse (2104045320031), we get a palindrome (132127585721231).

The spelling of 130023540401200 in words is "one hundred thirty trillion, twenty-three billion, five hundred forty million, four hundred one thousand, two hundred".

Divisors: 1 2 4 5 8 10 16 20 25 40 50 61 80 100 122 200 244 305 400 488 610 976 1220 1525 2440 3050 4880 6100 12200 24400 51899 102677 103798 205354 207596 259495 410708 415192 513385 518990 821416 830384 1026770 1037980 1297475 1642832 2053540 2075960 2566925 2594950 3165839 4107080 4151920 5133850 5189900 6263297 6331678 8214160 10267700 10379800 12526594 12663356 15829195 20535400 20759600 25053188 25326712 31316485 31658390 41070800 50106376 50653424 62632970 63316780 79145975 100212752 125265940 126633560 156582425 158291950 250531880 253267120 313164850 316583900 501063760 626329700 633167800 1252659400 1266335600 2505318800 5328833623 10657667246 21315334492 26644168115 42630668984 53288336230 85261337968 106576672460 133220840575 213153344920 266441681150 325058851003 426306689840 532883362300 650117702006 1065766724600 1300235404012 1625294255015 2131533449200 2600470808024 3250588510030 5200941616048 6501177020060 8126471275075 13002354040120 16252942550150 26004708080240 32505885100300 65011770200600 130023540401200