Base | Representation |
---|---|
bin | 1011110100110110000110… |
… | …1001111111110101011000 |
3 | 1201001000201212222110010202 |
4 | 2331031201221333311120 |
5 | 3201013112111414222 |
6 | 43353133522401332 |
7 | 2511254115602603 |
oct | 275154151776530 |
9 | 51030655873122 |
10 | 13002504404312 |
11 | 4163370841825 |
12 | 155bb80500248 |
13 | 73419179a467 |
14 | 32d4788a133a |
15 | 178359482892 |
hex | bd361a7fd58 |
13002504404312 has 8 divisors (see below), whose sum is σ = 24379695758100. Its totient is φ = 6501252202152.
The previous prime is 13002504404299. The next prime is 13002504404347. The reversal of 13002504404312 is 21340440520031.
It is a tau number, because it is divible by the number of its divisors (8).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 812656525262 + ... + 812656525277.
Almost surely, 213002504404312 is an apocalyptic number.
It is an amenable number.
13002504404312 is a deficient number, since it is larger than the sum of its proper divisors (11377191353788).
13002504404312 is a wasteful number, since it uses less digits than its factorization.
13002504404312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1625313050545 (or 1625313050541 counting only the distinct ones).
The product of its (nonzero) digits is 11520, while the sum is 29.
Adding to 13002504404312 its reverse (21340440520031), we get a palindrome (34342944924343).
The spelling of 13002504404312 in words is "thirteen trillion, two billion, five hundred four million, four hundred four thousand, three hundred twelve".
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