Base | Representation |
---|---|
bin | 11101100100000111010101… |
… | …011101000001010110011000 |
3 | 122001101021120121012202012121 |
4 | 131210013111131001112120 |
5 | 114020312424240402040 |
6 | 1140312415053351024 |
7 | 36250001560116361 |
oct | 3544072535012630 |
9 | 561337517182177 |
10 | 130025126106520 |
11 | 38480389a36a17 |
12 | 126bb8a7798474 |
13 | 5772416c72c38 |
14 | 241736d1b0b68 |
15 | 10073ba37ac4a |
hex | 7641d5741598 |
130025126106520 has 64 divisors (see below), whose sum is σ = 292702636800000. Its totient is φ = 51984079087488.
The previous prime is 130025126106487. The next prime is 130025126106529. The reversal of 130025126106520 is 25601621520031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130025126106529) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3089709399 + ... + 3089751481.
It is an arithmetic number, because the mean of its divisors is an integer number (4573478700000).
Almost surely, 2130025126106520 is an apocalyptic number.
130025126106520 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130025126106520 is an abundant number, since it is smaller than the sum of its proper divisors (162677510693480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130025126106520 is a wasteful number, since it uses less digits than its factorization.
130025126106520 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 78832 (or 78828 counting only the distinct ones).
The product of its (nonzero) digits is 21600, while the sum is 34.
Adding to 130025126106520 its reverse (25601621520031), we get a palindrome (155626747626551).
The spelling of 130025126106520 in words is "one hundred thirty trillion, twenty-five billion, one hundred twenty-six million, one hundred six thousand, five hundred twenty".
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