Base | Representation |
---|---|
bin | 11101100100001101000000… |
… | …010001000110001101101000 |
3 | 122001101212021210222120101101 |
4 | 131210031000101012031220 |
5 | 114020412411024010440 |
6 | 1140315303055131144 |
7 | 36250305451600510 |
oct | 3544150021061550 |
9 | 561355253876341 |
10 | 130031213110120 |
11 | 38482a22991903 |
12 | 12700b06213ab4 |
13 | 5772b77081b0a |
14 | 241778978a840 |
15 | 100762494c69a |
hex | 764340446368 |
130031213110120 has 64 divisors (see below), whose sum is σ = 334598337561600. Its totient is φ = 44551148743680.
The previous prime is 130031213110087. The next prime is 130031213110243. The reversal of 130031213110120 is 21011312130031.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 160958161 + ... + 161764000.
It is an arithmetic number, because the mean of its divisors is an integer number (5228099024400).
Almost surely, 2130031213110120 is an apocalyptic number.
130031213110120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130031213110120 is an abundant number, since it is smaller than the sum of its proper divisors (204567124451480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130031213110120 is a wasteful number, since it uses less digits than its factorization.
130031213110120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 322723618 (or 322723614 counting only the distinct ones).
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 130031213110120 its reverse (21011312130031), we get a palindrome (151042525240151).
The spelling of 130031213110120 in words is "one hundred thirty trillion, thirty-one billion, two hundred thirteen million, one hundred ten thousand, one hundred twenty".
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