130031254443 has 4 divisors (see below), whose sum is σ = 173375005928. Its totient is φ = 86687502960.

The previous prime is 130031254421. The next prime is 130031254471. The reversal of 130031254443 is 344452130031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 344452130031 = 3 ⋅114817376677.

It is not a de Polignac number, because 130031254443 - 2¹⁴ = 130031238059 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 130031254443.

It is not an unprimeable number, because it can be changed into a prime (130031250443) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21671875738 + ... + 21671875743.

It is an arithmetic number, because the mean of its divisors is an integer number (43343751482).

Almost surely, 2^130031254443 is an apocalyptic number.

130031254443 is a deficient number, since it is larger than the sum of its proper divisors (43343751485).

130031254443 is an equidigital number, since it uses as much as digits as its factorization.

130031254443 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43343751484.

The product of its (nonzero) digits is 17280, while the sum is 30.

Adding to 130031254443 its reverse (344452130031), we get a palindrome (474483384474).

The spelling of 130031254443 in words is "one hundred thirty billion, thirty-one million, two hundred fifty-four thousand, four hundred forty-three".