Base | Representation |
---|---|
bin | 111100100011001110… |
… | …1110111101110101100 |
3 | 110102122002202010122211 |
4 | 1321012131313232230 |
5 | 4112301000120234 |
6 | 135422513020204 |
7 | 12252203266120 |
oct | 1710635675654 |
9 | 412562663584 |
10 | 130031254444 |
11 | 50167287053 |
12 | 2124b254664 |
13 | c3534c87a0 |
14 | 64176c3580 |
15 | 35b0989164 |
hex | 1e46777bac |
130031254444 has 24 divisors (see below), whose sum is σ = 280067318048. Its totient is φ = 51440935680.
The previous prime is 130031254421. The next prime is 130031254471. The reversal of 130031254444 is 444452130031.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 178613997 + ... + 178614724.
Almost surely, 2130031254444 is an apocalyptic number.
130031254444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.
It is an amenable number.
130031254444 is an abundant number, since it is smaller than the sum of its proper divisors (150036063604).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130031254444 is a wasteful number, since it uses less digits than its factorization.
130031254444 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 357228745 (or 357228743 counting only the distinct ones).
The product of its (nonzero) digits is 23040, while the sum is 31.
Adding to 130031254444 its reverse (444452130031), we get a palindrome (574483384475).
The spelling of 130031254444 in words is "one hundred thirty billion, thirty-one million, two hundred fifty-four thousand, four hundred forty-four".
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