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13003133110010 = 251300313311001
BaseRepresentation
bin1011110100111000011100…
…1000010100011011111010
31201001002100201000000012222
42331032013020110123322
53201020404034010020
643353320142004042
72511305521530041
oct275160710243372
951032321000188
1013003133110010
11416366371670a
121560116b76622
13734261b06b74
1432d4d819b558
15178394770b25
hexbd3872146fa

13003133110010 has 8 divisors (see below), whose sum is σ = 23405639598036. Its totient is φ = 5201253244000.

The previous prime is 13003133110007. The next prime is 13003133110027. The reversal of 13003133110010 is 1001133130031.

It can be written as a sum of positive squares in 2 ways, for example, as 11414850116569 + 1588282993441 = 3378587^2 + 1260271^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650156655491 + ... + 650156655510.

Almost surely, 213003133110010 is an apocalyptic number.

13003133110010 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13003133110010 is a deficient number, since it is larger than the sum of its proper divisors (10402506488026).

13003133110010 is a wasteful number, since it uses less digits than its factorization.

13003133110010 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1300313311008.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13003133110010 its reverse (1001133130031), we get a palindrome (14004266240041).

The spelling of 13003133110010 in words is "thirteen trillion, three billion, one hundred thirty-three million, one hundred ten thousand, ten".

Divisors: 1 2 5 10 1300313311001 2600626622002 6501566555005 13003133110010