Base | Representation |
---|---|
bin | 111100100011010000… |
… | …0110011001001011110 |
3 | 110102122011012010200220 |
4 | 1321012200303021132 |
5 | 4112301144201420 |
6 | 135422541302210 |
7 | 12252212644164 |
oct | 1710640631136 |
9 | 412564163626 |
10 | 130032022110 |
11 | 50167760891 |
12 | 2124b564966 |
13 | c353707023 |
14 | 6417843234 |
15 | 35b0a8b840 |
hex | 1e4683325e |
130032022110 has 16 divisors (see below), whose sum is σ = 312076853136. Its totient is φ = 34675205888.
The previous prime is 130032022091. The next prime is 130032022111. The reversal of 130032022110 is 11220230031.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 130032022110.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130032022111) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2167200339 + ... + 2167200398.
It is an arithmetic number, because the mean of its divisors is an integer number (19504803321).
Almost surely, 2130032022110 is an apocalyptic number.
130032022110 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130032022110 is an abundant number, since it is smaller than the sum of its proper divisors (182044831026).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130032022110 is a wasteful number, since it uses less digits than its factorization.
130032022110 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4334400747.
The product of its (nonzero) digits is 72, while the sum is 15.
Adding to 130032022110 its reverse (11220230031), we get a palindrome (141252252141).
The spelling of 130032022110 in words is "one hundred thirty billion, thirty-two million, twenty-two thousand, one hundred ten".
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