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1300323000047 is a prime number
BaseRepresentation
bin10010111011000001010…
…010100101111011101111
311121022100202010112222212
4102323001102211323233
5132301030142000142
62433205442401035
7162642134063441
oct22730122457357
94538322115885
101300323000047
11461511485985
1219001766017b
1395809cb9026
1446d16428491
1523c57478d82
hex12ec14a5eef

1300323000047 has 2 divisors, whose sum is σ = 1300323000048. Its totient is φ = 1300323000046.

The previous prime is 1300322999999. The next prime is 1300323000059. The reversal of 1300323000047 is 7400003230031.

It is a happy number.

It is a strong prime.

It is an emirp because it is prime and its reverse (7400003230031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1300323000047 - 226 = 1300255891183 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1300322999986 and 1300323000031.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1300323900047) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650161500023 + 650161500024.

It is an arithmetic number, because the mean of its divisors is an integer number (650161500024).

Almost surely, 21300323000047 is an apocalyptic number.

1300323000047 is a deficient number, since it is larger than the sum of its proper divisors (1).

1300323000047 is an equidigital number, since it uses as much as digits as its factorization.

1300323000047 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1512, while the sum is 23.

Adding to 1300323000047 its reverse (7400003230031), we get a palindrome (8700326230078).

The spelling of 1300323000047 in words is "one trillion, three hundred billion, three hundred twenty-three million, forty-seven", and thus it is an aban number.