Search a number
-
+
1300332100103 = 11231157909261
BaseRepresentation
bin10010111011000001110…
…101010011101000000111
311121022101101020212220222
4102323001311103220013
5132301040004200403
62433210405414555
7162642304324301
oct22730165235007
94538341225828
101300332100103
11461516630993
1219001a70a45b
139580bb5408a
1446d17716971
1523c58175338
hex12ec1d53a07

1300332100103 has 4 divisors (see below), whose sum is σ = 1301490010488. Its totient is φ = 1299174189720.

The previous prime is 1300332100099. The next prime is 1300332100121. The reversal of 1300332100103 is 3010012330031.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1300332100103 - 22 = 1300332100099 is a prime.

It is a super-2 number, since 2×13003321001032 (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300332100703) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 578953508 + ... + 578955753.

It is an arithmetic number, because the mean of its divisors is an integer number (325372502622).

Almost surely, 21300332100103 is an apocalyptic number.

1300332100103 is a deficient number, since it is larger than the sum of its proper divisors (1157910385).

1300332100103 is a wasteful number, since it uses less digits than its factorization.

1300332100103 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1157910384.

The product of its (nonzero) digits is 162, while the sum is 17.

Adding to 1300332100103 its reverse (3010012330031), we get a palindrome (4310344430134).

The spelling of 1300332100103 in words is "one trillion, three hundred billion, three hundred thirty-two million, one hundred thousand, one hundred three".

Divisors: 1 1123 1157909261 1300332100103