Base | Representation |
---|---|
bin | 11000001110001100… |
… | …10111011011100000 |
3 | 1020120021100012211122 |
4 | 30013012113123200 |
5 | 203113011324412 |
6 | 5550213031412 |
7 | 640152162122 |
oct | 140706273340 |
9 | 36507305748 |
10 | 13004011232 |
11 | 5573475123 |
12 | 262b025568 |
13 | 12c3177704 |
14 | 8b50d1212 |
15 | 511995572 |
hex | 3071976e0 |
13004011232 has 24 divisors (see below), whose sum is σ = 26021350152. Its totient is φ = 6395414400.
The previous prime is 13004011219. The next prime is 13004011261. The reversal of 13004011232 is 23211040031.
It is a self number, because there is not a number n which added to its sum of digits gives 13004011232.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3328994 + ... + 3332897.
It is an arithmetic number, because the mean of its divisors is an integer number (1084222923).
Almost surely, 213004011232 is an apocalyptic number.
It is an amenable number.
13004011232 is an abundant number, since it is smaller than the sum of its proper divisors (13017338920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004011232 is an equidigital number, since it uses as much as digits as its factorization.
13004011232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6661962 (or 6661954 counting only the distinct ones).
The product of its (nonzero) digits is 144, while the sum is 17.
Adding to 13004011232 its reverse (23211040031), we get a palindrome (36215051263).
The spelling of 13004011232 in words is "thirteen billion, four million, eleven thousand, two hundred thirty-two".
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