1300402120118 has 4 divisors (see below), whose sum is σ = 1950603180180. Its totient is φ = 650201060058.

The previous prime is 1300402120117. The next prime is 1300402120163. The reversal of 1300402120118 is 8110212040031.

It is a semiprime because it is the product of two primes.

It is a junction number, because it is equal to n+sod(n) for n = 1300402120093 and 1300402120102.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300402120117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 325100530028 + ... + 325100530031.

It is an arithmetic number, because the mean of its divisors is an integer number (487650795045).

Almost surely, 2^{1300402120118} is an apocalyptic number.

1300402120118 is a deficient number, since it is larger than the sum of its proper divisors (650201060062).

1300402120118 is an equidigital number, since it uses as much as digits as its factorization.

1300402120118 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 650201060061.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 1300402120118 its reverse (8110212040031), we get a palindrome (9410614160149).

The spelling of 1300402120118 in words is "one trillion, three hundred billion, four hundred two million, one hundred twenty thousand, one hundred eighteen".