Base | Representation |
---|---|
bin | 1011110100111011110010… |
… | …0110001100011101010100 |
3 | 1201001011200012220112221102 |
4 | 2331032330212030131110 |
5 | 3201024223203242400 |
6 | 43353545144205232 |
7 | 2511336663232445 |
oct | 275167446143524 |
9 | 51034605815842 |
10 | 13004030134100 |
11 | 4163a83aa6135 |
12 | 1560327469818 |
13 | 7343758cab55 |
14 | 32d5813812cc |
15 | 1783e83b09d5 |
hex | bd3bc98c754 |
13004030134100 has 36 divisors (see below), whose sum is σ = 28233496849404. Its totient is φ = 5198892890880.
The previous prime is 13004030134097. The next prime is 13004030134127. The reversal of 13004030134100 is 143103040031.
It can be written as a sum of positive squares in 6 ways, for example, as 209716370704 + 12794313763396 = 457948^2 + 3576914^2 .
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 33797279 + ... + 34179878.
Almost surely, 213004030134100 is an apocalyptic number.
13004030134100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13004030134100 is an abundant number, since it is smaller than the sum of its proper divisors (15229466715304).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13004030134100 is a wasteful number, since it uses less digits than its factorization.
13004030134100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 67979084 (or 67979077 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 13004030134100 its reverse (143103040031), we get a palindrome (13147133174131).
The spelling of 13004030134100 in words is "thirteen trillion, four billion, thirty million, one hundred thirty-four thousand, one hundred".
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