13004044013232 has 120 divisors (see below), whose sum is σ = 37023147420480. Its totient is φ = 4259709590400.

The previous prime is 13004044013227. The next prime is 13004044013243. The reversal of 13004044013232 is 23231044040031.

13004044013232 is a `hidden beast` number, since 13 + 0 + 0 + 404 + 4 + 0 + 13 + 232 = 666.

It is a junction number, because it is equal to n+sod(n) for n = 13004044013196 and 13004044013205.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23953663 + ... + 24490529.

It is an arithmetic number, because the mean of its divisors is an integer number (308526228504).

Almost surely, 2^{13004044013232} is an apocalyptic number.

13004044013232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13004044013232, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18511573710240).

13004044013232 is an abundant number, since it is smaller than the sum of its proper divisors (24019103407248).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13004044013232 is a wasteful number, since it uses less digits than its factorization.

13004044013232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 539791 (or 539782 counting only the distinct ones).

The product of its (nonzero) digits is 6912, while the sum is 27.

Adding to 13004044013232 its reverse (23231044040031), we get a palindrome (36235088053263).

The spelling of 13004044013232 in words is "thirteen trillion, four billion, forty-four million, thirteen thousand, two hundred thirty-two".