1300409568120 has 512 divisors, whose sum is σ = 4459452641280. Its totient is φ = 300940738560.

The previous prime is 1300409568061. The next prime is 1300409568127. The reversal of 1300409568120 is 218659040031.

It is a Harshad number since it is a multiple of its sum of digits (39).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300409568127) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 1164197802 + ... + 1164198918.

It is an arithmetic number, because the mean of its divisors is an integer number (8709868440).

Almost surely, 2^{1300409568120} is an apocalyptic number.

1300409568120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300409568120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2229726320640).

1300409568120 is an abundant number, since it is smaller than the sum of its proper divisors (3159043073160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300409568120 is a wasteful number, since it uses less digits than its factorization.

1300409568120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1695 (or 1691 counting only the distinct ones).

The product of its (nonzero) digits is 51840, while the sum is 39.

The spelling of 1300409568120 in words is "one trillion, three hundred billion, four hundred nine million, five hundred sixty-eight thousand, one hundred twenty".