13004125153 has 2 divisors, whose sum is σ = 13004125154. Its totient is φ = 13004125152.

The previous prime is 13004125151. The next prime is 13004125223. The reversal of 13004125153 is 35152140031.

It is a happy number.

13004125153 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10470814929 + 2533310224 = 102327^2 + 50332^2 .

It is a cyclic number.

It is not a de Polignac number, because 13004125153 - 2¹ = 13004125151 is a prime.

Together with 13004125151, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (13004125151) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6502062576 + 6502062577.

It is an arithmetic number, because the mean of its divisors is an integer number (6502062577).

Almost surely, 2^13004125153 is an apocalyptic number.

It is an amenable number.

13004125153 is a deficient number, since it is larger than the sum of its proper divisors (1).

13004125153 is an equidigital number, since it uses as much as digits as its factorization.

13004125153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1800, while the sum is 25.

Adding to 13004125153 its reverse (35152140031), we get a palindrome (48156265184).

The spelling of 13004125153 in words is "thirteen billion, four million, one hundred twenty-five thousand, one hundred fifty-three".