Base | Representation |
---|---|
bin | 111100100011100011… |
… | …0010000001000000000 |
3 | 110102122211122221111012 |
4 | 1321013012100020000 |
5 | 4112311202341003 |
6 | 135423531540052 |
7 | 12252362255144 |
oct | 1710706201000 |
9 | 412584587435 |
10 | 130041840128 |
11 | 50172257252 |
12 | 212528ba628 |
13 | c355763ac5 |
14 | 6418c7b224 |
15 | 35b187a8d8 |
hex | 1e47190200 |
130041840128 has 30 divisors (see below), whose sum is σ = 259845996861. Its totient is φ = 65016840192.
The previous prime is 130041840091. The next prime is 130041840143. The reversal of 130041840128 is 821048140031.
It is a happy number.
It is a powerful number, because all its prime factors have an exponent greater than 1 and also an Achilles number because it is not a perfect power.
It can be written as a sum of positive squares in 2 ways, for example, as 124546879744 + 5494960384 = 352912^2 + 74128^2 .
It is an ABA number since it can be written as A⋅BA, here for A=2, B=254992.
It is a super-2 number, since 2×1300418401282 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (32).
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 130041840094 and 130041840103.
It is an unprimeable number.
It is a polite number, since it can be written in 2 ways as a sum of consecutive naturals, for example, 8151776 + ... + 8167712.
Almost surely, 2130041840128 is an apocalyptic number.
It is an amenable number.
130041840128 is a deficient number, since it is larger than the sum of its proper divisors (129804156733).
130041840128 is an frugal number, since it uses more digits than its factorization.
130041840128 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31892 (or 15939 counting only the distinct ones).
The product of its (nonzero) digits is 6144, while the sum is 32.
Multiplying 130041840128 by its sum of digits (32), we get a square (4161338884096 = 20399362).
130041840128 divided by its sum of digits (32) gives a square (4063807504 = 637482).
Adding to 130041840128 its reverse (821048140031), we get a palindrome (951089980159).
The spelling of 130041840128 in words is "one hundred thirty billion, forty-one million, eight hundred forty thousand, one hundred twenty-eight".
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