Base | Representation |
---|---|
bin | 11000001110001110… |
… | …00101100100101011 |
3 | 1020120021200211002202 |
4 | 30013013011210223 |
5 | 203113033401420 |
6 | 5550221050415 |
7 | 640153610135 |
oct | 140707054453 |
9 | 36507624082 |
10 | 13004200235 |
11 | 5573594124 |
12 | 262b0b6a0b |
13 | 12c3212750 |
14 | 8b5140055 |
15 | 5119d1575 |
hex | 3071c592b |
13004200235 has 32 divisors (see below), whose sum is σ = 17835733440. Its totient is φ = 9017008128.
The previous prime is 13004200211. The next prime is 13004200249. The reversal of 13004200235 is 53200240031.
It is a happy number.
It is a cyclic number.
It is not a de Polignac number, because 13004200235 - 224 = 12987423019 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 464876 + ... + 492054.
It is an arithmetic number, because the mean of its divisors is an integer number (557366670).
Almost surely, 213004200235 is an apocalyptic number.
13004200235 is a deficient number, since it is larger than the sum of its proper divisors (4831533205).
13004200235 is a wasteful number, since it uses less digits than its factorization.
13004200235 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 27647.
The product of its (nonzero) digits is 720, while the sum is 20.
Adding to 13004200235 its reverse (53200240031), we get a palindrome (66204440266).
The spelling of 13004200235 in words is "thirteen billion, four million, two hundred thousand, two hundred thirty-five".
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