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1300422013341 = 31139406727677
BaseRepresentation
bin10010111011000111001…
…100010011000110011101
311121022121122102221200220
4102323013030103012131
5132301231013411331
62433223340511553
7162644445506103
oct22730714230635
94538548387626
101300422013341
11461562363050
1219004484b5b9
1395824675689
1446d2563dc73
1523c60ed6296
hex12ec731319d

1300422013341 has 8 divisors (see below), whose sum is σ = 1891522928544. Its totient is φ = 788134553520.

The previous prime is 1300422013309. The next prime is 1300422013381. The reversal of 1300422013341 is 1433102240031.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 1300422013341 - 25 = 1300422013309 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1300422013301) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19703363806 + ... + 19703363871.

It is an arithmetic number, because the mean of its divisors is an integer number (236440366068).

Almost surely, 21300422013341 is an apocalyptic number.

1300422013341 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

1300422013341 is a deficient number, since it is larger than the sum of its proper divisors (591100915203).

1300422013341 is a wasteful number, since it uses less digits than its factorization.

1300422013341 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 39406727691.

The product of its (nonzero) digits is 1728, while the sum is 24.

Adding to 1300422013341 its reverse (1433102240031), we get a palindrome (2733524253372).

The spelling of 1300422013341 in words is "one trillion, three hundred billion, four hundred twenty-two million, thirteen thousand, three hundred forty-one".

Divisors: 1 3 11 33 39406727677 118220183031 433474004447 1300422013341