Base | Representation |
---|---|
bin | 111100100011100100… |
… | …0011110101011000000 |
3 | 110102122212202121102002 |
4 | 1321013020132223000 |
5 | 4112311330032000 |
6 | 135423552243132 |
7 | 12252400236326 |
oct | 1710710365300 |
9 | 412585677362 |
10 | 130042424000 |
11 | 50172615995 |
12 | 21252b404a8 |
13 | c3559097a8 |
14 | 6418d8dd16 |
15 | 35b19438d5 |
hex | 1e4721eac0 |
130042424000 has 56 divisors (see below), whose sum is σ = 322050082848. Its totient is φ = 52016966400.
The previous prime is 130042423997. The next prime is 130042424021. The reversal of 130042424000 is 424240031.
It is a super-2 number, since 2×1300424240002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8119652 + ... + 8135651.
Almost surely, 2130042424000 is an apocalyptic number.
130042424000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130042424000 is an abundant number, since it is smaller than the sum of its proper divisors (192007658848).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130042424000 is an equidigital number, since it uses as much as digits as its factorization.
130042424000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 16255330 (or 16255310 counting only the distinct ones).
The product of its (nonzero) digits is 768, while the sum is 20.
Adding to 130042424000 its reverse (424240031), we get a palindrome (130466664031).
The spelling of 130042424000 in words is "one hundred thirty billion, forty-two million, four hundred twenty-four thousand".
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