130043340031 has 8 divisors (see below), whose sum is σ = 141872808528. Its totient is φ = 118215096000.

The previous prime is 130043340001. The next prime is 130043340073.

It is a happy number.

130043340031 is nontrivially palindromic in base 10.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 130043340031 - 2¹⁹ = 130042815743 is a prime.

It is a super-2 number, since 2×130043340031² (a number of 23 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130043339984 and 130043340011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130043340001) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 76560 + ... + 515701.

It is an arithmetic number, because the mean of its divisors is an integer number (17734101066).

Almost surely, 2^130043340031 is an apocalyptic number.

130043340031 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

130043340031 is a deficient number, since it is larger than the sum of its proper divisors (11829468497).

130043340031 is a wasteful number, since it uses less digits than its factorization.

130043340031 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 612233.

The product of its (nonzero) digits is 1296, while the sum is 22.

It can be divided in two parts, 130043 and 340031, that added together give a palindrome (470074).

The spelling of 130043340031 in words is "one hundred thirty billion, forty-three million, three hundred forty thousand, thirty-one".