1300440040 has 64 divisors (see below), whose sum is σ = 3035394000. Its totient is φ = 500828160.

The previous prime is 1300440019. The next prime is 1300440067. The reversal of 1300440040 is 400440031.

It can be written as a sum of positive squares in 8 ways, for example, as 753722116 + 546717924 = 27454^2 + 23382^2 .

It is a super-2 number, since 2×1300440040² = 3382288595270403200, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1300439996 and 1300440023.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 473070 + ... + 475810.

Almost surely, 2^1300440040 is an apocalyptic number.

1300440040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1300440040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1517697000).

1300440040 is an abundant number, since it is smaller than the sum of its proper divisors (1734953960).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1300440040 is a wasteful number, since it uses less digits than its factorization.

1300440040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3190 (or 3186 counting only the distinct ones).

The product of its (nonzero) digits is 192, while the sum is 16.

The square root of 1300440040 is about 36061.6144951942. The cubic root of 1300440040 is about 1091.5160118680.

Adding to 1300440040 its reverse (400440031), we get a palindrome (1700880071).

Subtracting from 1300440040 its reverse (400440031), we obtain a palindrome (900000009).

The spelling of 1300440040 in words is "one billion, three hundred million, four hundred forty thousand, forty".