Base | Representation |
---|---|
bin | 11000001110010101… |
… | …01001101100111010 |
3 | 1020120100110021212201 |
4 | 30013022221230322 |
5 | 203113303302100 |
6 | 5550253100414 |
7 | 640164551314 |
oct | 140712515472 |
9 | 36510407781 |
10 | 13005134650 |
11 | 5574072172 |
12 | 262b48770a |
13 | 12c347bb61 |
14 | 8b53047b4 |
15 | 511b1836a |
hex | 3072a9b3a |
13005134650 has 24 divisors (see below), whose sum is σ = 24214655520. Its totient is φ = 5196654960.
The previous prime is 13005134633. The next prime is 13005134677. The reversal of 13005134650 is 5643150031.
13005134650 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 86140 + ... + 182839.
It is an arithmetic number, because the mean of its divisors is an integer number (1008943980).
Almost surely, 213005134650 is an apocalyptic number.
13005134650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
13005134650 is a deficient number, since it is larger than the sum of its proper divisors (11209520870).
13005134650 is a wasteful number, since it uses less digits than its factorization.
13005134650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 269958 (or 269953 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 28.
Adding to 13005134650 its reverse (5643150031), we get a palindrome (18648284681).
The spelling of 13005134650 in words is "thirteen billion, five million, one hundred thirty-four thousand, six hundred fifty".
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