Base | Representation |
---|---|
bin | 11101100100100000010001… |
… | …010100001111010000000100 |
3 | 122001110211200112110200212021 |
4 | 131210200101110033100010 |
5 | 114021232242430202100 |
6 | 1140333003532132524 |
7 | 36251640216366241 |
oct | 3544402124172004 |
9 | 561424615420767 |
10 | 130051900240900 |
11 | 38490779270400 |
12 | 12704b1a307144 |
13 | 5774ac2c112c1 |
14 | 241878d01a5c8 |
15 | 1007e35b97a1a |
hex | 76481150f404 |
130051900240900 has 243 divisors, whose sum is σ = 317714164574709. Its totient is φ = 46172636664000.
The previous prime is 130051900240883. The next prime is 130051900240919. The reversal of 130051900240900 is 9042009150031.
The square root of 130051900240900 is 11404030.
It is a perfect power (a square), and thus also a powerful number.
It can be written as a sum of positive squares in only one way, i.e., 46818684086724 + 83233216154176 = 6842418^2 + 9123224^2 .
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 80 ways as a sum of consecutive naturals, for example, 53941060695 + ... + 53941063105.
Almost surely, 2130051900240900 is an apocalyptic number.
130051900240900 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130051900240900 is the 11404030-th square number.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130051900240900
130051900240900 is an abundant number, since it is smaller than the sum of its proper divisors (187662264333809).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130051900240900 is an equidigital number, since it uses as much as digits as its factorization.
130051900240900 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4944 (or 2472 counting only the distinct ones).
The product of its (nonzero) digits is 9720, while the sum is 34.
Adding to 130051900240900 its reverse (9042009150031), we get a palindrome (139093909390931).
The spelling of 130051900240900 in words is "one hundred thirty trillion, fifty-one billion, nine hundred million, two hundred forty thousand, nine hundred".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.081 sec. • engine limits •