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130062552677 is a prime number
BaseRepresentation
bin111100100100001010…
…1010000111001100101
3110102201021122020202122
41321020111100321211
54112332003141202
6135425551515325
712253033312451
oct1711025207145
9412637566678
10130062552677
1150182a13962
1221259828b45
13c359b36655
14641b90d661
1535b35bc9a2
hex1e48550e65

130062552677 has 2 divisors, whose sum is σ = 130062552678. Its totient is φ = 130062552676.

The previous prime is 130062552667. The next prime is 130062552679. The reversal of 130062552677 is 776255260031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 68201411716 + 61861140961 = 261154^2 + 248719^2 .

It is a cyclic number.

It is not a de Polignac number, because 130062552677 - 210 = 130062551653 is a prime.

It is a super-3 number, since 3×1300625526773 (a number of 34 digits) contains 333 as substring.

Together with 130062552679, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (130062552679) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65031276338 + 65031276339.

It is an arithmetic number, because the mean of its divisors is an integer number (65031276339).

Almost surely, 2130062552677 is an apocalyptic number.

It is an amenable number.

130062552677 is a deficient number, since it is larger than the sum of its proper divisors (1).

130062552677 is an equidigital number, since it uses as much as digits as its factorization.

130062552677 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 529200, while the sum is 44.

The spelling of 130062552677 in words is "one hundred thirty billion, sixty-two million, five hundred fifty-two thousand, six hundred seventy-seven".