1301011211 has 4 divisors (see below), whose sum is σ = 1301104872. Its totient is φ = 1300917552.

The previous prime is 1301011177. The next prime is 1301011219. The reversal of 1301011211 is 1121101031.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 1121101031 = 43 ⋅26072117.

It is a cyclic number.

It is not a de Polignac number, because 1301011211 - 2²² = 1296816907 is a prime.

It is a super-4 number, since 4×1301011211⁴ (a number of 38 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301011192 and 1301011201.

It is not an unprimeable number, because it can be changed into a prime (1301011219) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21386 + ... + 55311.

It is an arithmetic number, because the mean of its divisors is an integer number (325276218).

Almost surely, 2^1301011211 is an apocalyptic number.

1301011211 is a deficient number, since it is larger than the sum of its proper divisors (93661).

1301011211 is an equidigital number, since it uses as much as digits as its factorization.

1301011211 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 93660.

The product of its (nonzero) digits is 6, while the sum is 11.

The square root of 1301011211 is about 36069.5330022444. The cubic root of 1301011211 is about 1091.6757913837.

Adding to 1301011211 its reverse (1121101031), we get a palindrome (2422112242).

The spelling of 1301011211 in words is "one billion, three hundred one million, eleven thousand, two hundred eleven".