Base | Representation |
---|---|
bin | 111100100101010111… |
… | …1111100001101000111 |
3 | 110102211002221021112220 |
4 | 1321022233330031013 |
5 | 4112422343201411 |
6 | 135434000543423 |
7 | 12254035051056 |
oct | 1711257741507 |
9 | 412732837486 |
10 | 130103100231 |
11 | 501a3898935 |
12 | 2126b321b73 |
13 | c3653624a0 |
14 | 642306639d |
15 | 35b6e2bb06 |
hex | 1e4abfc347 |
130103100231 has 64 divisors (see below), whose sum is σ = 204359823360. Its totient is φ = 72860497920.
The previous prime is 130103100223. The next prime is 130103100233. The reversal of 130103100231 is 132001301031.
It is not a de Polignac number, because 130103100231 - 23 = 130103100223 is a prime.
It is a super-2 number, since 2×1301031002312 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 130103100231.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130103100233) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 34794360 + ... + 34798098.
It is an arithmetic number, because the mean of its divisors is an integer number (3193122240).
Almost surely, 2130103100231 is an apocalyptic number.
130103100231 is a deficient number, since it is larger than the sum of its proper divisors (74256723129).
130103100231 is a wasteful number, since it uses less digits than its factorization.
130103100231 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5496.
The product of its (nonzero) digits is 54, while the sum is 15.
Adding to 130103100231 its reverse (132001301031), we get a palindrome (262104401262).
The spelling of 130103100231 in words is "one hundred thirty billion, one hundred three million, one hundred thousand, two hundred thirty-one".
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