13010331113 has 4 divisors (see below), whose sum is σ = 14011125828. Its totient is φ = 12009536400.

The previous prime is 13010331101. The next prime is 13010331119. The reversal of 13010331113 is 31113301031.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 31113301031 = 389 ⋅79982779.

It can be written as a sum of positive squares in 2 ways, for example, as 1095080464 + 11915250649 = 33092^2 + 109157^2 .

It is a cyclic number.

It is not a de Polignac number, because 13010331113 - 2¹⁰ = 13010330089 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13010331091 and 13010331100.

It is not an unprimeable number, because it can be changed into a prime (13010331119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500397338 + ... + 500397363.

It is an arithmetic number, because the mean of its divisors is an integer number (3502781457).

Almost surely, 2^13010331113 is an apocalyptic number.

13010331113 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

It is an amenable number.

13010331113 is a deficient number, since it is larger than the sum of its proper divisors (1000794715).

13010331113 is a wasteful number, since it uses less digits than its factorization.

13010331113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1000794714.

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 13010331113 its reverse (31113301031), we get a palindrome (44123632144).

The spelling of 13010331113 in words is "thirteen billion, ten million, three hundred thirty-one thousand, one hundred thirteen".