Base | Representation |
---|---|
bin | 11000001111000010… |
… | …00111000111111111 |
3 | 1020120202112102021010 |
4 | 30013201013013333 |
5 | 203121310203320 |
6 | 5551023210303 |
7 | 640265602503 |
oct | 140741070777 |
9 | 36522472233 |
10 | 13011022335 |
11 | 5577423723 |
12 | 2631446993 |
13 | 12c47609ac |
14 | 8b5dd8303 |
15 | 5123ccae0 |
hex | 3078471ff |
13011022335 has 32 divisors (see below), whose sum is σ = 22064873472. Its totient is φ = 6524305920.
The previous prime is 13011022327. The next prime is 13011022337. The reversal of 13011022335 is 53322011031.
It is not a de Polignac number, because 13011022335 - 23 = 13011022327 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13011022337) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 226962 + ... + 278448.
It is an arithmetic number, because the mean of its divisors is an integer number (689527296).
Almost surely, 213011022335 is an apocalyptic number.
13011022335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13011022335 is a deficient number, since it is larger than the sum of its proper divisors (9053851137).
13011022335 is a wasteful number, since it uses less digits than its factorization.
13011022335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 52503.
The product of its (nonzero) digits is 540, while the sum is 21.
Adding to 13011022335 its reverse (53322011031), we get a palindrome (66333033366).
The spelling of 13011022335 in words is "thirteen billion, eleven million, twenty-two thousand, three hundred thirty-five".
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