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1301104101641 is a prime number
BaseRepresentation
bin10010111011101111110…
…110010000100100001001
311121101101011220121221112
4102323233312100210021
5132304130122223031
62433415144220105
7163000400246531
oct22735766204411
94541334817845
101301104101641
11461882389093
121901b516a635
1395902a83016
1446d8c0744c1
1523ca0d1b62b
hex12eefd90909

1301104101641 has 2 divisors, whose sum is σ = 1301104101642. Its totient is φ = 1301104101640.

The previous prime is 1301104101571. The next prime is 1301104101679. The reversal of 1301104101641 is 1461014011031.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1296874550416 + 4229551225 = 1138804^2 + 65035^2 .

It is a cyclic number.

It is not a de Polignac number, because 1301104101641 - 210 = 1301104100617 is a prime.

It is not a weakly prime, because it can be changed into another prime (1301104103641) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650552050820 + 650552050821.

It is an arithmetic number, because the mean of its divisors is an integer number (650552050821).

Almost surely, 21301104101641 is an apocalyptic number.

It is an amenable number.

1301104101641 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301104101641 is an equidigital number, since it uses as much as digits as its factorization.

1301104101641 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 288, while the sum is 23.

Adding to 1301104101641 its reverse (1461014011031), we get a palindrome (2762118112672).

The spelling of 1301104101641 in words is "one trillion, three hundred one billion, one hundred four million, one hundred one thousand, six hundred forty-one".