1301110100951 has 2 divisors, whose sum is σ = 1301110100952. Its totient is φ = 1301110100950.

The previous prime is 1301110100933. The next prime is 1301110101023. The reversal of 1301110100951 is 1590010111031.

It is a weak prime.

It is an emirp because it is prime and its reverse (1590010111031) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1301110100951 - 2³⁸ = 1026232194007 is a prime.

It is a super-2 number, since 2×1301110100951² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1301110100351) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650555050475 + 650555050476.

It is an arithmetic number, because the mean of its divisors is an integer number (650555050476).

Almost surely, 2^{1301110100951} is an apocalyptic number.

1301110100951 is a deficient number, since it is larger than the sum of its proper divisors (1).

1301110100951 is an equidigital number, since it uses as much as digits as its factorization.

1301110100951 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 135, while the sum is 23.

Adding to 1301110100951 its reverse (1590010111031), we get a palindrome (2891120211982).

The spelling of 1301110100951 in words is "one trillion, three hundred one billion, one hundred ten million, one hundred thousand, nine hundred fifty-one".