Base | Representation |
---|---|
bin | 10010111011110000001… |
… | …101001001010000011111 |
3 | 11121101101121012102112212 |
4 | 102323300031021100133 |
5 | 132304133141213043 |
6 | 2433415520551035 |
7 | 163000502244455 |
oct | 22736015112037 |
9 | 4541347172485 |
10 | 1301110101023 |
11 | 461885806557 |
12 | 1901b718247b |
13 | 959040a3955 |
14 | 46d8cb969d5 |
15 | 23ca1604018 |
hex | 12ef034941f |
1301110101023 has 2 divisors, whose sum is σ = 1301110101024. Its totient is φ = 1301110101022.
The previous prime is 1301110100951. The next prime is 1301110101059. The reversal of 1301110101023 is 3201010111031.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1301110101023 - 212 = 1301110096927 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1301110100989 and 1301110101007.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1301110101923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 650555050511 + 650555050512.
It is an arithmetic number, because the mean of its divisors is an integer number (650555050512).
Almost surely, 21301110101023 is an apocalyptic number.
1301110101023 is a deficient number, since it is larger than the sum of its proper divisors (1).
1301110101023 is an equidigital number, since it uses as much as digits as its factorization.
1301110101023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 1301110101023 its reverse (3201010111031), we get a palindrome (4502120212054).
The spelling of 1301110101023 in words is "one trillion, three hundred one billion, one hundred ten million, one hundred one thousand, twenty-three".
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