13011103117 has 2 divisors, whose sum is σ = 13011103118. Its totient is φ = 13011103116.

The previous prime is 13011103087. The next prime is 13011103163. The reversal of 13011103117 is 71130111031.

13011103117 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12765836196 + 245266921 = 112986^2 + 15661^2 .

It is a cyclic number.

It is not a de Polignac number, because 13011103117 - 2²³ = 13002714509 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13011103094 and 13011103103.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13011103177) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505551558 + 6505551559.

It is an arithmetic number, because the mean of its divisors is an integer number (6505551559).

Almost surely, 2^13011103117 is an apocalyptic number.

It is an amenable number.

13011103117 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011103117 is an equidigital number, since it uses as much as digits as its factorization.

13011103117 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 63, while the sum is 19.

Adding to 13011103117 its reverse (71130111031), we get a palindrome (84141214148).

The spelling of 13011103117 in words is "thirteen billion, eleven million, one hundred three thousand, one hundred seventeen".