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13011121223 = 79164697737
BaseRepresentation
bin11000001111000010…
…11111010001000111
31020120202201102220122
430013201133101013
5203121321334343
65551025252155
7640266464012
oct140741372107
936522642818
1013011121223
115577490a51
12263149405b
1312c47969c9
148b6022379
155123ec068
hex30785f447

13011121223 has 4 divisors (see below), whose sum is σ = 13175819040. Its totient is φ = 12846423408.

The previous prime is 13011121217. The next prime is 13011121231. The reversal of 13011121223 is 32212111031.

13011121223 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13011121223 - 214 = 13011104839 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011121423) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 82348790 + ... + 82348947.

It is an arithmetic number, because the mean of its divisors is an integer number (3293954760).

Almost surely, 213011121223 is an apocalyptic number.

13011121223 is a deficient number, since it is larger than the sum of its proper divisors (164697817).

13011121223 is an equidigital number, since it uses as much as digits as its factorization.

13011121223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 164697816.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13011121223 its reverse (32212111031), we get a palindrome (45223232254).

The spelling of 13011121223 in words is "thirteen billion, eleven million, one hundred twenty-one thousand, two hundred twenty-three".

Divisors: 1 79 164697737 13011121223