Base | Representation |
---|---|
bin | 111100100101100111… |
… | …1010101101100011100 |
3 | 110102211200102110011220 |
4 | 1321023033111230130 |
5 | 4112432000043400 |
6 | 135434453213340 |
7 | 12254165031552 |
oct | 1711317255434 |
9 | 412750373156 |
10 | 130111331100 |
11 | 501a84aa903 |
12 | 21272031250 |
13 | c366c84a1a |
14 | 64241a9bd2 |
15 | 35b7a057a0 |
hex | 1e4b3d5b1c |
130111331100 has 144 divisors (see below), whose sum is σ = 386133785856. Its totient is φ = 33806528000.
The previous prime is 130111331093. The next prime is 130111331137. The reversal of 130111331100 is 1133111031.
It is a super-2 number, since 2×1301113311002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 130111331100.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 10165705 + ... + 10178495.
It is an arithmetic number, because the mean of its divisors is an integer number (2681484624).
Almost surely, 2130111331100 is an apocalyptic number.
130111331100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130111331100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (193066892928).
130111331100 is an abundant number, since it is smaller than the sum of its proper divisors (256022454756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130111331100 is a wasteful number, since it uses less digits than its factorization.
130111331100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 13676 (or 13669 counting only the distinct ones).
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 130111331100 its reverse (1133111031), we get a palindrome (131244442131).
The spelling of 130111331100 in words is "one hundred thirty billion, one hundred eleven million, three hundred thirty-one thousand, one hundred".
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