13011211303101 has 96 divisors (see below), whose sum is σ = 20737201080960. Its totient is φ = 7795943884800.

The previous prime is 13011211303093. The next prime is 13011211303127. The reversal of 13011211303101 is 10130311211031.

13011211303101 is a `hidden beast` number, since 1 + 301 + 1 + 21 + 1 + 30 + 310 + 1 = 666.

It is not a de Polignac number, because 13011211303101 - 2³ = 13011211303093 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011211303301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 3085416745 + ... + 3085420961.

It is an arithmetic number, because the mean of its divisors is an integer number (216012511260).

Almost surely, 2^{13011211303101} is an apocalyptic number.

13011211303101 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13011211303101 is a deficient number, since it is larger than the sum of its proper divisors (7725989777859).

13011211303101 is a wasteful number, since it uses less digits than its factorization.

13011211303101 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5387 (or 5384 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 18.

Adding to 13011211303101 its reverse (10130311211031), we get a palindrome (23141522514132).

The spelling of 13011211303101 in words is "thirteen trillion, eleven billion, two hundred eleven million, three hundred three thousand, one hundred one".