Base | Representation |
---|---|
bin | 11101100101011000011011… |
… | …011101101011101101101111 |
3 | 122001200121022221011102102202 |
4 | 131211120123131223231233 |
5 | 114023224241201443322 |
6 | 1140420415230012115 |
7 | 36256203416220641 |
oct | 3545303335535557 |
9 | 561617287142382 |
10 | 130112200031087 |
11 | 3850430199924a |
12 | 1271474864703b |
13 | 577a6b27c4921 |
14 | 241b66d62a891 |
15 | 10097b48b7292 |
hex | 76561b76bb6f |
130112200031087 has 2 divisors, whose sum is σ = 130112200031088. Its totient is φ = 130112200031086.
The previous prime is 130112200031071. The next prime is 130112200031089. The reversal of 130112200031087 is 780130002211031.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 130112200031087 - 24 = 130112200031071 is a prime.
Together with 130112200031089, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (130112200031089) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65056100015543 + 65056100015544.
It is an arithmetic number, because the mean of its divisors is an integer number (65056100015544).
Almost surely, 2130112200031087 is an apocalyptic number.
130112200031087 is a deficient number, since it is larger than the sum of its proper divisors (1).
130112200031087 is an equidigital number, since it uses as much as digits as its factorization.
130112200031087 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 29.
The spelling of 130112200031087 in words is "one hundred thirty trillion, one hundred twelve billion, two hundred million, thirty-one thousand, eighty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.073 sec. • engine limits •