13011244442141 has 8 divisors (see below), whose sum is σ = 14577708761184. Its totient is φ = 11508717442320.

The previous prime is 13011244442117. The next prime is 13011244442149. The reversal of 13011244442141 is 14124444211031.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13011244442141 - 2²⁶ = 13011177333277 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 13011244442098 and 13011244442107.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011244442149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 15984329375 + ... + 15984330188.

It is an arithmetic number, because the mean of its divisors is an integer number (1822213595148).

Almost surely, 2^{13011244442141} is an apocalyptic number.

13011244442141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

13011244442141 is a deficient number, since it is larger than the sum of its proper divisors (1566464319043).

13011244442141 is a wasteful number, since it uses less digits than its factorization.

13011244442141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 31968659611.

The product of its (nonzero) digits is 12288, while the sum is 32.

Adding to 13011244442141 its reverse (14124444211031), we get a palindrome (27135688653172).

The spelling of 13011244442141 in words is "thirteen trillion, eleven billion, two hundred forty-four million, four hundred forty-two thousand, one hundred forty-one".