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13011303310 = 251301130331
BaseRepresentation
bin11000001111000100…
…01011101110001110
31020120210001200200121
430013202023232032
5203121343201220
65551033215154
7640301152615
oct140742135616
936523050617
1013011303310
1155775a5835
1226315614ba
1312c482b855
148b606c87c
15512435eaa
hex30788bb8e

13011303310 has 8 divisors (see below), whose sum is σ = 23420345976. Its totient is φ = 5204521320.

The previous prime is 13011303293. The next prime is 13011303373. The reversal of 13011303310 is 1330311031.

13011303310 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×130113033102 (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 650565156 + ... + 650565175.

It is an arithmetic number, because the mean of its divisors is an integer number (2927543247).

Almost surely, 213011303310 is an apocalyptic number.

13011303310 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13011303310 is a deficient number, since it is larger than the sum of its proper divisors (10409042666).

13011303310 is a wasteful number, since it uses less digits than its factorization.

13011303310 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1301130338.

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13011303310 its reverse (1330311031), we get a palindrome (14341614341).

The spelling of 13011303310 in words is "thirteen billion, eleven million, three hundred three thousand, three hundred ten".

Divisors: 1 2 5 10 1301130331 2602260662 6505651655 13011303310