13011304451 has 2 divisors, whose sum is σ = 13011304452. Its totient is φ = 13011304450.

The previous prime is 13011304409. The next prime is 13011304457. The reversal of 13011304451 is 15440311031.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13011304451 - 2⁶ = 13011304387 is a prime.

It is a super-3 number, since 3×13011304451³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (13011304457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6505652225 + 6505652226.

It is an arithmetic number, because the mean of its divisors is an integer number (6505652226).

Almost surely, 2^13011304451 is an apocalyptic number.

13011304451 is a deficient number, since it is larger than the sum of its proper divisors (1).

13011304451 is an equidigital number, since it uses as much as digits as its factorization.

13011304451 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 13011304451 its reverse (15440311031), we get a palindrome (28451615482).

The spelling of 13011304451 in words is "thirteen billion, eleven million, three hundred four thousand, four hundred fifty-one".