13011310032 has 40 divisors (see below), whose sum is σ = 38414344896. Its totient is φ = 3717517056.

The previous prime is 13011310031. The next prime is 13011310079. The reversal of 13011310032 is 23001311031.

It is a junction number, because it is equal to n+sod(n) for n = 13011309993 and 13011310020.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13011310031) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19361733 + ... + 19362404.

Almost surely, 2^13011310032 is an apocalyptic number.

13011310032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13011310032 is an abundant number, since it is smaller than the sum of its proper divisors (25403034864).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011310032 is a wasteful number, since it uses less digits than its factorization.

13011310032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38724155 (or 38724149 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13011310032 its reverse (23001311031), we get a palindrome (36012621063).

Subtracting 13011310032 from its reverse (23001311031), we obtain a palindrome (9990000999).

The spelling of 13011310032 in words is "thirteen billion, eleven million, three hundred ten thousand, thirty-two".