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130113113300 = 22521301131133
BaseRepresentation
bin111100100101101011…
…0001000110011010100
3110102211210202222220022
41321023112020303110
54112432424111200
6135434555324312
712254216133512
oct1711326106324
9412753688808
10130113113300
11501a95078a5
1221272750698
13c367459c91
1464245114b2
1535b7c58885
hex1e4b588cd4

130113113300 has 18 divisors (see below), whose sum is σ = 282345456078. Its totient is φ = 52045245280.

The previous prime is 130113113239. The next prime is 130113113321. The reversal of 130113113300 is 3311311031.

It can be written as a sum of positive squares in 3 ways, for example, as 14394436 + 130098718864 = 3794^2 + 360692^2 .

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 650565467 + ... + 650565666.

It is an arithmetic number, because the mean of its divisors is an integer number (15685858671).

Almost surely, 2130113113300 is an apocalyptic number.

130113113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130113113300 is an abundant number, since it is smaller than the sum of its proper divisors (152232342778).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130113113300 is a wasteful number, since it uses less digits than its factorization.

130113113300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1301131147 (or 1301131140 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 17.

Adding to 130113113300 its reverse (3311311031), we get a palindrome (133424424331).

The spelling of 130113113300 in words is "one hundred thirty billion, one hundred thirteen million, one hundred thirteen thousand, three hundred".

Divisors: 1 2 4 5 10 20 25 50 100 1301131133 2602262266 5204524532 6505655665 13011311330 26022622660 32528278325 65056556650 130113113300