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13011312303000 = 23325311592227583
BaseRepresentation
bin1011110101010110111010…
…1001011101101110011000
31201001212110201121001200200
42331111232221131232120
53201134131422144000
643401151522302200
72512015306524534
oct275255651355630
951055421531620
1013011312303000
114167080655440
12156181a1b7960
13734c664ca72b
1432da7258cbc4
151786c2865500
hexbd56ea5db98

13011312303000 has 384 divisors, whose sum is σ = 48789435801600. Its totient is φ = 3100794144000.

The previous prime is 13011312302999. The next prime is 13011312303019. The reversal of 13011312303000 is 30321311031.

It is a happy number.

13011312303000 is a `hidden beast` number, since 1 + 3 + 0 + 1 + 131 + 230 + 300 + 0 = 666.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 4727209 + ... + 6954791.

It is an arithmetic number, because the mean of its divisors is an integer number (127055822400).

Almost surely, 213011312303000 is an apocalyptic number.

13011312303000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13011312303000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (24394717900800).

13011312303000 is an abundant number, since it is smaller than the sum of its proper divisors (35778123498600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13011312303000 is a wasteful number, since it uses less digits than its factorization.

13011312303000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2227680 (or 2227663 counting only the distinct ones).

The product of its (nonzero) digits is 162, while the sum is 18.

Adding to 13011312303000 its reverse (30321311031), we get a palindrome (13041633614031).

The spelling of 13011312303000 in words is "thirteen trillion, eleven billion, three hundred twelve million, three hundred three thousand".