Base | Representation |
---|---|
bin | 11000001111001010… |
… | …10101110100110001 |
3 | 1020120211121202020021 |
4 | 30013211111310301 |
5 | 203122101143441 |
6 | 5551103043441 |
7 | 640311201223 |
oct | 140745256461 |
9 | 36524552207 |
10 | 13012131121 |
11 | 5578010780 |
12 | 26318a0581 |
13 | 12c4a5b592 |
14 | 8b6206413 |
15 | 51254b3d1 |
hex | 307955d31 |
13012131121 has 4 divisors (see below), whose sum is σ = 14195052144. Its totient is φ = 11829210100.
The previous prime is 13012131089. The next prime is 13012131137. The reversal of 13012131121 is 12113121031.
It is a happy number.
13012131121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 13012131121 - 25 = 13012131089 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 13012131095 and 13012131104.
It is not an unprimeable number, because it can be changed into a prime (13012131421) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 591460495 + ... + 591460516.
It is an arithmetic number, because the mean of its divisors is an integer number (3548763036).
Almost surely, 213012131121 is an apocalyptic number.
13012131121 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
It is an amenable number.
13012131121 is a deficient number, since it is larger than the sum of its proper divisors (1182921023).
13012131121 is a wasteful number, since it uses less digits than its factorization.
13012131121 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1182921022.
The product of its (nonzero) digits is 36, while the sum is 16.
Adding to 13012131121 its reverse (12113121031), we get a palindrome (25125252152).
The spelling of 13012131121 in words is "thirteen billion, twelve million, one hundred thirty-one thousand, one hundred twenty-one".
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