Base | Representation |
---|---|
bin | 111100100101111111… |
… | …1110010010101101101 |
3 | 110102212120022200122012 |
4 | 1321023333302111231 |
5 | 4112443223000331 |
6 | 135440025331005 |
7 | 12254411005523 |
oct | 1711377622555 |
9 | 412776280565 |
10 | 130124031341 |
11 | 50204694777 |
12 | 21276336a65 |
13 | c3697b0665 |
14 | 6425b54313 |
15 | 35b8bb382b |
hex | 1e4bff256d |
130124031341 has 4 divisors (see below), whose sum is σ = 130805309184. Its totient is φ = 129442753500.
The previous prime is 130124031337. The next prime is 130124031353. The reversal of 130124031341 is 143130421031.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 143130421031 = 13 ⋅11010032387.
It is a cyclic number.
It is not a de Polignac number, because 130124031341 - 22 = 130124031337 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130124031371) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 340638635 + ... + 340639016.
It is an arithmetic number, because the mean of its divisors is an integer number (32701327296).
Almost surely, 2130124031341 is an apocalyptic number.
It is an amenable number.
130124031341 is a deficient number, since it is larger than the sum of its proper divisors (681277843).
130124031341 is an equidigital number, since it uses as much as digits as its factorization.
130124031341 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 681277842.
The product of its (nonzero) digits is 864, while the sum is 23.
Adding to 130124031341 its reverse (143130421031), we get a palindrome (273254452372).
The spelling of 130124031341 in words is "one hundred thirty billion, one hundred twenty-four million, thirty-one thousand, three hundred forty-one".
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